SOLUTION: A farmer is given 36 feet of fencing material. He wants to experiment with different size rectangles while using all 36 feet of the material. He is given the width and needs to fig

Question 850479: A farmer is given 36 feet of fencing material. He wants to experiment with different size rectangles while using all 36 feet of the material. He is given the width and needs to figure out the length and area.
The widths he is provided with are as follows. He must figure out the length and areas that correspond with the given widths
Width: 1 Length: Area:
Width: 2 Length: Area:
Width: 3 Length: Area:
Width: 4 Length: Area:
Width: 5 Length: Area:
Width: 6 Length: Area:
Width: 7 Length: Area:
Width: 8 Length: Area:
Width: 9 Length: Area:
Width: 10 Length: Area:
After figuring out the length and area, we must write a function that could represent the relationship between the length and the width. Then we write an equation giving the length as a function of the width.
Then the farmer must write a function for the area of the rectangle as a function of the width.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
perimeter p=2W+2L
area a=W*L
perimeter 36
Width: 1 Length: 17 Area:17
Width: 2 Length: 16 Area:32
Width: 3 Length: 15 Area:45
Width: 4 Length: 14 Area:64
Width: 5 Length: 13 Area:65
Width: 6 Length: 12 Area:72
Width: 7 Length: 11 Area:77
Width: 8 Length: 10 Area:80
Width: 9 Length: 9 Area:81
Width: 10 Length: 8 Area:80
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