# SOLUTION: A chemist needs 100 milliliters of a 63% solution but has only 55% and 95% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

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 Click here to see ALL problems on Miscellaneous Word Problems Question 83763: A chemist needs 100 milliliters of a 63% solution but has only 55% and 95% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.Answer by stanbon(57983)   (Show Source): You can put this solution on YOUR website!A chemist needs 100 milliliters of a 63% solution but has only 55% and 95% solutions available. Find how many milliliters of each that should be mixed to get the desired solution. --------------- Let amount of 55% solution be "x" ml ; Amt of active ingredient = 0.55x ml --------------- Amount of 95% solution is "100-x" ml ; Amt of active ingre. = 0.95(100-x) = 95-0.95x ml --------------------- Amount of 63% solution is 100 ml ; Amt of active ingre. 0.63(100) = 63 ml --------------- EQUATION: active + active = active 0.55x + 95-0.95x = 63 -0.40x = -32 x= 80 ml (amount of 55% solution needed) 100-80 = 20 ml (amount of 95% solution needed) =========== Cheers, Stan H. San