SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
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Question 83369: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
Answer by jmichau3(2) (Show Source): You can put this solution on YOUR website!
ok well the best way to start is with an even interger.
Let 2n = an even integer
Then the next consecutive even integer will be 2n+2 and then 2n+4 will be the third.
then use what is given so come up with
(2n+4)^2 = (2n+2)^2 + 76.
Now solve for n, Which I will leave for you to do...
once you solve forn n, make sure to plug it back into your equations (ie 2n,2n+2, 2n+4) to find your consecutive numbers
If anything is unclear feel free to email me
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