# SOLUTION: The cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5 foot length with diameter 2 inches costs \$48.00, how much will a 8 foot leng

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: The cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5 foot length with diameter 2 inches costs \$48.00, how much will a 8 foot leng      Log On

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 Click here to see ALL problems on Miscellaneous Word Problems Question 83293: The cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5 foot length with diameter 2 inches costs \$48.00, how much will a 8 foot length with diameter 4 inches cost?Answer by vertciel(183)   (Show Source): You can put this solution on YOUR website!This is a proportion problem. We cannot compare the ratios until all the units are equal. Hence, we need to find the volume in terms of feet or inches and then set up a ratio. Find the volume of each tube first. Afterwards, set up a ratio in terms of: Volume/Price of Smaller Tube = Volume/Price of Larger Tube Please write back if further help is needed. --- Volume = Pi(radius^2) x height For example, in the first cylinder, the radius is 1 inch and the height would be 5 feet. In order to find the volume, you would need to convert all measurements to inches or feet. Plug the values into the formula and you have the volume. Do the same for the other cylinder. Again, convert the values to either inches or feet. Then, fill in the ratio. The only thing blank would be the "price of larger tube", because that is what you want to find out. I won't calculate this for you because I want you to try to solve this problem. It's more exciting for you.