SOLUTION: A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have?
{dimes, nickels}
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Question 78591: A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have?
{dimes, nickels}
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
D=NUMBER OF DIMES
D+2=NUMBER OF NICKELS
10D+5(D+2)=115
10D+5D+10=115
15D=115-10
15D=105
D=105/15
D=7 NUMBER OF DIMES. THEREFORE THE NUMBER OF NICKELS IS:
7+2=9 IS THE NUMBER OF NICKELS.
PROOF
10*7+5*9=115
70+45=115
115=115
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