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put this solution on YOUR website!Distance(d) = rate(r) times time(t) or d=rt, t=d/r and r=d/t
We are told that the speed (rate) on both days are the same
Let t=driving time on the second day of trip
Then t+2=driving time on first day of trip
Rate on second day=270/t
Rate on first day=360/(t+2)
But we are told that:
Rate on second day=rate on first day, so
270/t=360/(t+2) multiply both sides by t(t+2) to get rid of fractions
(270(t)(t+2))/t=(360(t)(t+2))/(t+2) simplify
270(t+2)=360t get rid of parens
270t+540=360t subtract 270t from both sides
360t-270t=270t-270t+540 collect like terms
90t=540 divide both sides by 90
t=6 hours-------------------driving time second day
t+2=6+2=8 hours----------------------driving time first day
ck
r=d/t
r=360/(6+2)=360/8=45 mph
r=270/6=45 mph
Hope this helps-----ptaylor
