SOLUTION: Please help me solve:In a birthday party,out of 53 children,8 children have neither an ice cream not a cold drink.If 30 children have ice cream and 23 children have cold drink,find
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Question 762139: Please help me solve:In a birthday party,out of 53 children,8 children have neither an ice cream not a cold drink.If 30 children have ice cream and 23 children have cold drink,find:
i]how many children have only ice cream
ii]how many children have only cold drinks
iii]how many children have both cold drinks and ice cream
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Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Total children: 53
Children that had neither: 8
Children that had something: 53 - 8 = 45
Children that had ice cream plus children that had cold drinks = 30 + 23 = 53.
53 is 8 more than 45, so 8 of the children must have been counted twice when adding the 30 plus the 23. Hence, 8 had both. If 30 had ice cream and 8 had both, then 30 minus 8 = 22 had ice cream only. If 23 had cold drinks and 8 had both, then 23 minus 8 = 15 had cold drinks only.
Check:
22 ice cream only
15 cold drink only
8 both
8 nothing
22 + 15 + 8 + 8 = 53
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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