SOLUTION: Please help me solve this equation:
Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?
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Question 758293: Please help me solve this equation:
Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?
Found 2 solutions by rfer, MathTherapy:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
4(2x+7) > x +70
8x+28 > x+70
7x > 70-28
7x > 42
x > 42/7
x > 6
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation:
Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?
Let the number be N
Then: 4(2N + 7) = N + 70
8N + 28 = N + 70
7N = 42
N, or number = , or
You can do the check!!
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