SOLUTION: Five years ago, person A's height was exactly 1.15 times person B's height. In these five years, A has grown 10cm taller and B has grown 35cm taller, and B is now 4cm taller than A

Algebra.Com
Question 758197: Five years ago, person A's height was exactly 1.15 times person B's height. In these five years, A has grown 10cm taller and B has grown 35cm taller, and B is now 4cm taller than A. B's current height is [   ] cm.
Found 2 solutions by anoosh57, MathTherapy:
Answer by anoosh57(1)   (Show Source): You can put this solution on YOUR website!
35
Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

Five years ago, person A's height was exactly 1.15 times person B's height. In these five years, A has grown 10cm taller and B has grown 35cm taller, and B is now 4cm taller than A. B's current height is [   ] cm.

B's current height: cm
You can do the check!!
===================
If you need a complete and detailed solution, let me know!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.
RELATED QUESTIONS

A person has to be at least 48 inches tall to ride a roller coaster. Jill, who is 12... (answered by josmiceli)
Two people begin working on the same day for the same company. The starting salary of... (answered by josgarithmetic)
a man's age is three times his son's age. Ten years ago he was five times his son's age.... (answered by JBarnum)
Two people begin working on the same day for the same company. The starting salary of... (answered by josgarithmetic)
Hi I am having problems completely solving this worded problem Five years ago... (answered by josmiceli,josgarithmetic)
Harry is x years old now. Three years ago, Jenny was twice Harry’s age. In three years’ (answered by KMST)
1. The sum of the ages of a mother and a daughter is 50yrs. Five years ago, the mother’s (answered by algebrahouse.com)
C's age is 6 more than the sum of the ages of A and B. Five years from now A will be half (answered by ankor@dixie-net.com)
If a die is rolled 30 times, there are 630 different sequences possible. What fraction... (answered by DrBeeee)