SOLUTION: kelly has ten cards numbered 1 to 10. what is the probability of picking two even-numbered cards one after the other, if the first card is not replaced?

Question 739639: kelly has ten cards numbered 1 to 10. what is the probability of picking two even-numbered cards one after the other, if the first card is not replaced?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
P(2 even) = P(even)*P(even after 1 isn't replaced)

P(2 even) = (5/10)*(4/9)

P(2 even) = (5*4)/(10*9)

P(2 even) = 20/90

P(2 even) = 2/9

The answer as a fraction is 2/9

The answer as a decimal is 0.222222 (this is approximate)

The answer as a percentage is 22.2222 % (this is approximate)
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