SOLUTION: Solve the problem.
When interest is compounded continuously, the balance in an account after t years is given by P(t)= Poekt, where Po is the initial investment and k is the int
Algebra.Com
Question 726650: Solve the problem.
When interest is compounded continuously, the balance in an account after t years is given by P(t)= Poekt, where Po is the initial investment and k is the interest rate. Suppose that Po is invested in a savings account where interest is compunded continuously at 8% per year. Express P(t) in terms of Po and 0.08.
Possible answers are:
A) P(t)= Poo.08t
B) None
C) P(t)=Poe0.08t
D) P(t)=Poe8t
E) P(t)=Poe0.08
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
with
= amount originally invested (principal at time zero),
= annual interest rate (expressed as a decimal), and
= time in years,
gives the balance as a function of time.
If the annual interest is 8%, the interest rate expressed as a decimal is
--> and
All you had to do is write instead of in the formula.
RELATED QUESTIONS
When interest is compounded continuously, the balance in an account after t years is... (answered by stanbon)
I am to recall that, when interest is compounded continuously, the balance in an account... (answered by stanbon)
Please help me When interest is compounded continuously, the balance in an account after (answered by stanbon,jim_thompson5910)
When interest is compounded continuously, the balance in an account after t years is... (answered by jim_thompson5910)
This problem is a story problem using the formula listed below.
When interest is... (answered by stanbon)
I have a problem setting up the equation for these 2 word problems. Any help would be... (answered by vleith)
P₀ is invested in a savings account where interest is compounded continuously at... (answered by Theo)
when interest is compounded continouously, the balance in an account after t years is... (answered by Theo)
I am to recall that, when interest is compounded continuously, the balance in an account... (answered by stanbon)