SOLUTION: the sum of two numbers is 58. the smaller number is 18 less then the larger number. what are the numbers?

Question 723700:
the sum of two numbers is 58. the smaller number is 18 less then the larger number. what are the numbers?
Found 2 solutions by checkley79, lynnlo:
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
X+Y=58
X-Y=18 ADD
----------------
2X=76
X=76/2
X=38 ANS. FOR THE LARGER NUMBER.
38+Y=58
Y=58-38
Y=20 ANS. FOR THE SMALLER NUMBER.
PROOF:
38-20=18
18=18
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
SUM==========================58
SMALLER NUMBER 18 LESS=======20
LARGER NUMBER IS=============38
===============================
20+38=58
SMALLER NUMBER 20))+18=38 YOUR LARGER NUMBER
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