SOLUTION: A chemist uses an 80% acid solution and a 30% acid solution to make 200 liters of a 60% acid solution. How much of the 30% solution should be used. A. 60 L B. 80 L C. 100 L D.

Question 721770: A chemist uses an 80% acid solution and a 30% acid solution to make 200 liters of a 60% acid solution. How much of the 30% solution should be used.
A. 60 L
B. 80 L
C. 100 L
D. 120 L
Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A chemist uses an 80% acid solution and a 30% acid solution to make 200 liters of a 60% acid solution. How much of the 30% solution should be used.
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Equation:
acid + acid = acid
0.80x + 0.30(200-x) = 0.60*200
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Multiply thru by 100:
80x + 30*200 - 30x = 60*200
50x = 30*200
x = (3/5)200
x = 120 liters (amt. of 80% solution needed
200-120 = 80 liters (amt. of 30% solution needed)
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Cheers,
Stan H.
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A. 60 L
B. 80 L
C. 100 L
D. 120 L

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Assuming all concentrations are %w/v, you would have these:

x for 30% acid, y for 80% acid,
and .

Solve for x and y.
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