SOLUTION: Adult male height and weight: Here is the rule of thumb relating weight to height for adult males. If a man is 1 inch taller than another, then we expect him to be heavier by 5 lbs

Algebra.Com
Question 720015: Adult male height and weight: Here is the rule of thumb relating weight to height for adult males. If a man is 1 inch taller than another, then we expect him to be heavier by 5 lbs.
Explain why, according to this rule, among typical males the weight is a linear function of the height. and identify the slope.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Adult male height and weight: Here is the rule of thumb relating weight to height for adult males. If a man is 1 inch taller than another, then we expect him to be heavier by 5 lbs.
Explain why, according to this rule, among typical males the weight is a linear function of the height. and identify the slope.
-----
weight = slope*height + b
-----
Since weight increase by 5 for every inch of height, slope = 5.
====================
Cheers,
Stan H.

RELATED QUESTIONS

First of all I would like to know if the input depends on the output,,and this word... (answered by nyc_function)
Need help with this one! The height of adult males is normally distributed with mean... (answered by Fombitz)
According to the U.S National Center for Health Statistics, the mean height for adult... (answered by Theo)
Hi Can someone please check my work? I am having trouble understanding confidence... (answered by ewatrrr)
4. An elevator has a placard stating that the maximum capacity is 3800 lb — 26... (answered by Theo)
In the average adult male, for each 5 pounds of body weight about 3 pounds is water. How... (answered by ikleyn)
According to a study done by students, the height for Asian adult males is normally... (answered by Boreal)
According to the National Institute of Health, body mass on height and weight that... (answered by mathchemprofessor)
I am trying to find an equation for direct and indirect variation. The word problem I am... (answered by josgarithmetic,MathTherapy)