SOLUTION: Seven times one number decreased by twice another equals 27, and 3 times the first added to 5 times the second equals 35. Find the two numbers.

Question 716036: Seven times one number decreased by twice another equals 27, and 3 times the first added to 5 times the second equals 35. Find the two numbers.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Seven times one number decreased by twice another equals 27, and 3 times the first added to 5 times the second equals 35. Find the two numbers.
**
let x=first number
let y=2nd number
..
7x-2y=27
3x+5y=35
..
35x-10y=135
6x+10y=70
add
41x=205
x=5
2y=7x-27
2y=35-27
2y=8
y=4
..
1st number=5
2nd number=4

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