SOLUTION: one number is 6 less than 3 times another number and the sum of the two numbers is 38? How do I write this out? x-6<3y=38 I am intermediate algebra and we are not into multiple le

Question 709440: one number is 6 less than 3 times another number and the sum of the two numbers is 38? How do I write this out? x-6<3y=38 I am intermediate algebra and we are not into multiple letters yet so I know I need two problems am I on the right track?
Answer by aaronwiz(69) (Show Source): You can put this solution on YOUR website!
x=first number
3x-6=other number
so if you add them (x)+(3x-6)=38
now just solve and it will give you the answer for the first number x=11 plug it into the original equation to find the other number and you will get 27
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