SOLUTION: Oranges vary directly as blues squared and inversely as greens. When there are 16 oranges, there were 5 blues and 25 greens. How many oranges were there when there were 4 blues and
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Question 694631: Oranges vary directly as blues squared and inversely as greens. When there are 16 oranges, there were 5 blues and 25 greens. How many oranges were there when there were 4 blues and 8 greens.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Oranges vary directly as blues squared and inversely as greens. When there are 16 oranges, there were 5 blues and 25 greens. How many oranges were there when there were 4 blues and 8 greens.
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O = k*B^2/G
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Solve for "k" using "When there are 16 oranges, there were 5 blues and 25 greens"
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16 = k*5^2/25
k = 16
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Equation:
O = 16B^2/G
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. How many oranges were there when there were 4 blues and 8 greens.
O = 16*4^2/8
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O = 2*16
# of oranges = 32
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Cheers,
Stan H.
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