SOLUTION: Dear Sir/ Madam a pleasant day! please help me with a word problem about joint variation, I am not sure whether my answer is right or wrong.
If y varies jointly as x and the squ
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Question 688182: Dear Sir/ Madam a pleasant day! please help me with a word problem about joint variation, I am not sure whether my answer is right or wrong.
If y varies jointly as x and the square root of z, and inversely as the cube of w, and y = 8 when x=3, z=16 and w=2, find y when x=5, z=25 and w=2.
I answered 8/133.33, please help me and thank you so much!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If y varies jointly as x and the square root of z,
and inversely as the cube of w,
---
y = k*x*sqrt(z)/w^3
----
Solve for "k" using "y = 8 when x=3, z=16 and w=2"
8 = k*3*4/2^3
8 = k(3/2)
----
k = 16/3
=========================
Equation:
y = (16/3)*x*sqrt(z)/w^3
---------
Find y when x=5, z=25 and w=2.
---
y = (16/3)*5*5/8
y = (2/3)25
---
y = 16 2/3
---------------
Cheers,
Stan H.
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