SOLUTION: sixty-two feet of fencing was used to enclose a rectangular pen that was 11 feet wide. How long was the pen?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: sixty-two feet of fencing was used to enclose a rectangular pen that was 11 feet wide. How long was the pen?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   


Question 68469: sixty-two feet of fencing was used to enclose a rectangular pen that was 11 feet wide. How long was the pen?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
PERIMETERIS = 2 TIMES LENGTH + 2 TIMES WIDTH THUS
62=2*L+2*11
62=2L+22
62-22=2L
40=2L
40/2=L
20=LENGTH
PROOF
2*11+2*20=62
22+40=62
62=62