SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

Question 68054This question is from textbook
: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs. This question is from textbook

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
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Let the base length be "x".
The length of each of the equal sides is 4x-8.
EQUATION:
Sum of the lengths of the legs =29 cm
x+4x-8+4x-8=29
9x-16=29
9x=45
x=5 (length of the base)
4x-8=4*5-8=12 (length of one of the equal sides)
Cheers,
Stan H.
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