SOLUTION: There are four consecutive integers. Their sum is 100 decreased by twice the difference between the greatest and twice the least.

Question 677417: There are four consecutive integers. Their sum is 100 decreased by twice the difference between the greatest and twice the least.
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
Establish variables
x x+1 x+2 x+3
...
x+x+1+x+2+x+3=100-2((x+3)-2x)
4x + 6 = 100 - 2(x+3-2x)
Distribute the 2
4x + 6 = 100 - 2x - 2(3) - 2(-2x)
4x + 6 = 100 - 2x - 6 + 4x
4x - 4x + 2x = 100 - 6 - 6
2x = 88
x = 44
...
Integers are 44, 45, 46, 47
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