SOLUTION: the sum of two numbers is 18 seven times the smaller number minus twice the larger one is 36 what are the two numbers
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Question 676824: the sum of two numbers is 18 seven times the smaller number minus twice the larger one is 36 what are the two numbers
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x = one number
y = another number
...
x+y=18
7y-2x = 36
...
Rearrange the first equation as x = 18-y
Substitute into the second equation
7y - 2(18-y) = 36
Distribute the 2
7y - 2(18) - 2(-y) = 36
7y - 36 + 2y = 36
Isolate the y variable
9y = 36 + 36
9y = 72
Divide both sides by 9
x = 18-8 =
.....................
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