SOLUTION: The members of the science club agreed to contribute $480. if there had been 3 more members in the club each member would have had to pay $8 dollars less. how many members were in
Algebra.Com
Question 668635: The members of the science club agreed to contribute $480. if there had been 3 more members in the club each member would have had to pay $8 dollars less. how many members were in the science club originally.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
The members of the science club agreed to contribute $480. if there had been 3 more members in the club each member would have had to pay $8 dollars less. how many members were in the science club originally
*
let x=number of members in the science club originally
480/x=original club dues
480/(x+3)=club dues with 3 more members
..
480/x-480/(x+3)=8
LCD:x(x+3)
480(x+3)-480x=8x(x+3)
480x+1440-480x=8x^2+24x
8x^2+24x-1440=0
x^2+3x-180=0
factor
(x+15)(x-12)=0
x=-15 (reject, x>0)
x=12
x+3=15
number of members in the science club originally=12
RELATED QUESTIONS
The members of a mathematics club agreed to contribute equally to
provide a fund of... (answered by ikleyn)
Hi
the members of a club each contribute an equal amount to buy a computer. If there... (answered by greenestamps,ikleyn)
The computer club bought a $300 computer, the members sharing the cost equally. If there... (answered by reviewermath)
3 out of 8 students are members of the science club. If there are 560 students in the... (answered by ikleyn)
the ski club is planning to charter a bus to a ski resort. the cost will be $900 and each (answered by stanbon)
The members of a club agreed to raise P150,000 for charity but 25 of them failed to pay... (answered by richwmiller)
A school club has 60 members enrolled to go for a trip in bus.If 12 less members had... (answered by josgarithmetic)
A charity collected $2,040 in equal donations from their members to share the cost of a... (answered by bucky)
The Ski Club is planning to charter a bus to a ski resort. The cost will be $900 and each (answered by ikleyn,josgarithmetic)