SOLUTION: A motorboat traveling with the current went 6 mi in 1 h. Against the current, it took 3 h to travel the same distance. Find the rate of the boat in calm water and the rate of the c
Algebra.Com
Question 667156: A motorboat traveling with the current went 6 mi in 1 h. Against the current, it took 3 h to travel the same distance. Find the rate of the boat in calm water and the rate of the current
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
D=RT
6=R*1
R=6 MPH WITH THE CURRENT.
6=R*3
3R=6
R=6/3
R=2 MPH AGAINST THE CURRENT.
(6+2)/2= SPEED OF THE BOAT IN STILL WATER
8/2=4 MPH.
THUS THE SPEED OF THE CURRENT IS:
6-4=2 MPH.
PROOF:
6-2=4
2+2=4
RELATED QUESTIONS
A motorboat traveling with the current went 48 mi in 2 h. Traveling against the current,... (answered by mananth)
A motorboat traveling with the current went 75 mi in 3 h. Against the current, it took 5... (answered by ikleyn)
A motorboat traveling with the current went 105 mi in 5 h. Traveling against the... (answered by josgarithmetic)
A motor boat traveling with the current went 12 mi in 1 h. Against the current, it took 2 (answered by ankor@dixie-net.com)
A motorboat traveling with the current went 60 mi in 3 h. Against the current, it took 5... (answered by scott8148)
With Current, a motorboat travels 60 mi in 3 h. Against the current, it takes 2h longer... (answered by solver91311)
A cabin cruiser traveling with the current went 0 mi in 0 h. Against the current, it took (answered by Alan3354)
A cabin cruiser traveling with the current went 45 mi in 3 h. Against the current, it... (answered by Alan3354)
A motorboat traveling with the current went 45 miles in 3 hours. Against the current, it... (answered by josgarithmetic,MathTherapy)