SOLUTION: 1. How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman must bat third and the pitcher last?

Question 641952: 1. How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman must bat third and the pitcher last?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You have 3 slots locked up because "the center fielder must bat fourth, the second baseman must bat third and the pitcher last". So you have 9 - 3 = 6 players to arrange in 6 slots.

There are 6! = 6*5*4*3*2*1 = 720 different ways to arrange the 6 remaining players. So there are 720 different lineups.
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