SOLUTION: A rectangular garden is twice as long as it is wide and is surrounded by a sidewalk, that is 4 ft wide. The area of the sidewalk is 256 ft2. Find the dimensions of the garden.
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Question 626847: A rectangular garden is twice as long as it is wide and is surrounded by a sidewalk, that is 4 ft wide. The area of the sidewalk is 256 ft2. Find the dimensions of the garden.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Let be the width of the garden (in feet).
Since the garden is twice as long as it is wide,
its length must be .
With one piece of sidewalk on each side,
the dimensions (in feet) of the garden plus sidewalk are
and
It would look like this:
The area (in square feet) of the whole thing is
The area of the garden part only is
The difference is the area (in square feet) of the sidewalk only,
-->
Subtracting 64 from both sides of the equal sign we get
--> -->
Dividing both sides of the equal sign by 24 we get
--> -->
The garden is feet wide, and feet long
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