Hi,

Am not quite sure what it is You are not understanding. z = 

Here is the standard normal curve. z=values of 0,±1, ±2,±3 shown

for ex: 50% of the area under the normal curve is to the left and right of z=0

one  standard deviation from the mean(z= ±1)  accounts for about 68.2% of the set 

two standard deviations from the mean(z= ±2) account for about 95.4%

and three standard deviations from the mean(z= ±2) account for about 99.7%.





(A) P(z > 0.90) = 1 -P(z ≤ .90) = 1- NORMSDIST(.90) = 1-.8159 = .1841 or 18.41% 

 18.41% is the % of the Area to the right of the blue line



(B) P(-1.17 < z < 0) = .50 - NORMSDIST(-1.17)= .50-.121

(C) P(-0.58 < z < 1.57)  = NORMSDIST(1.57) - NORMSDIST(-.58) = .9418-.2801

 Here, the Excel function NORMSDIST is being used for the z-values. 

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