SOLUTION: John rents a booth for $35.00 a day and sells ice cream cones.
His cost for each cone is $2.00 and he sells the cones for $5.00 each.
If John wants to make at least a $200.00 pro
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Question 616950: John rents a booth for $35.00 a day and sells ice cream cones.
His cost for each cone is $2.00 and he sells the cones for $5.00 each.
If John wants to make at least a $200.00 profit for the day, how many ice cream cones must he sell?
a. 34
b. 78
c. 79
d. 118
Which would be the correct answer and please explain, the way to arrive at the answer... please..
Found 3 solutions by solver91311, richwmiller, MathTherapy:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
He sells them for $5 each, so his revenue function is \ =\ 5x)
where 
is the number sold. His cost function is \ =\ 2x\ +\ 35)
because of the $2 per cone cost plus the $35 fixed rental cost.
Profit is revenue minus cost, so:
\ =\ R(x)\ -\ C(x)\ =\ 5x\ -\ 2x\ -\ 35\ = 3x\ -\ 35)
So if you want the value of )
to be at least $200,
Solve for and round UP to the nearest whole number (because you can't sell a fraction of an ice cream cone).
John
My calculator said it, I believe it, that settles it
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
y=mx+b
profit=selling price minus costs
5-2=3 dollar profit on each cone
200=3x-35
235=3x
235/3=x
78.33=x
Since he can't sell part of cone, x must be a whole number.
79 is the minimum.
Answer by MathTherapy(10559) (Show Source): You can put this solution on YOUR website!
John rents a booth for $35.00 a day and sells ice cream cones.
His cost for each cone is $2.00 and he sells the cones for $5.00 each.
If John wants to make at least a $200.00 profit for the day, how many ice cream cones must he sell?
a. 34
b. 78
c. 79
d. 118
Which would be the correct answer and please explain, the way to arrive at the answer... please..
Remember that: Revenues – cost = profit
Let the amount of ice cream cones he has to sell to make a $200 profit be C
Then the cost of the cones he hopes to sell = 2C, and his total costs are: 2C + $35
His revenues from selling C ice cream cones, at $5 per cone = 5C
We now have:
Revenues – cost = profit, OR
, or
Since we don’t have fractional amounts of ice cream cones, we round up this amount to 79
This means that in order for him to make a $200 profit for the day, he has to sell AT LEAST ice cream cones (CHOICE C)
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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