SOLUTION: find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 6 times the third. What is the smallest integer? What is

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Question 616635: find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 6 times the third.
What is the smallest integer?
What is the second smallest integer?
What is the largest integer?

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
find three positive integers
What is the smallest integer?
What is the second smallest integer? (n+1)
What is the largest integer? (n+2)
product of the first and third, minus the second, is 1 more than 6 times the third.
n(n+2) - (n+1) = 6(n+2)+1
n^2 -5n -14 = 0
(n+2)(n-7) = 0, (tossing out the negative solution for n)
the three consecutive positive integers are: 7,8,9
CHECKING our Answer***
7*9 - 8 = 55 = 6*9 + 1

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