SOLUTION: I need help with this one. Jane and Terry went to Long Beach for a week. They needed to rent a car so they checked out two rental firms. Avis want $35 per day with no mileage

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Question 61433This question is from textbook college algebra
: I need help with this one.
Jane and Terry went to Long Beach for a week. They needed to rent a car so they checked out two rental firms. Avis want $35 per day with no mileage fee. Downtown Toyota wanted $150 per week (7 days) and $.19 per mile. How many miles would they have to drive before the Toyota price is more than the Avis price?
Thanks in advance for your help.
This question is from textbook college algebra

Answer by ptaylor(2198)   (Show Source): You can put this solution on YOUR website!
Let x=the number of miles they would have to drive before the Toyota price is
more than the Avis price.
Assumption: They can only rent from Toyota by the week - not by the day.
Thus, Avis would cost $245 for the same amount of time (7 days).
Now we know that when the cost of Toyota per week (minimum rental) (150+.19x) equals the cost of Avis per week ($245), any additional mileage would make the Toyota price more than the Avis price. Thus, our equation to solve is:
(150+.19x)=245 and
.19x=245-150
.19x=95
x=500 miles
Hope this helps--------------ptaylor

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