# SOLUTION: Tom wants to enclose a section of his lawn that is 30 yards long and 20 yards wide. He buys 125 yards of fencing. How much fencing is left over?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: Tom wants to enclose a section of his lawn that is 30 yards long and 20 yards wide. He buys 125 yards of fencing. How much fencing is left over?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Miscellaneous Word Problems Question 612402: Tom wants to enclose a section of his lawn that is 30 yards long and 20 yards wide. He buys 125 yards of fencing. How much fencing is left over?Answer by G8TORS(10)   (Show Source): You can put this solution on YOUR website!This is a perimeter of a rectangle problem. Perimeter (P) of a rectangle is the sum of all sides P = 2 x length + 2 x width. In this problem the Perimeter (P) = The amount needed for the area Tom wants to enclose Question: How many yards are leftover? Leftover = Amount bought – amount needed Given information: Rectangle = 30 yards long by 20 yards wide Amount Bought = 125 yards Step 1: Find the Perimeter(P)of rectangle 30 yards long and 20 yards wide. P = 2 x length + 2 x width. P = (2 x 30) + (2 x 20) P = 60 + 40 P = 100 Step 2: Find the yards leftover. Leftover = Bought – Needed Leftover = 125 - Perimeter Leftover = 125 - 100 Leftover = 25 Answer: 25 yards is leftover