SOLUTION: Adult tickets cost $18.00 children cost $8.00 there were 21 people total at the theatre and they collected $288.00 how many children attended?

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Question 60876: Adult tickets cost $18.00 children cost $8.00 there were 21 people total at the theatre and they collected $288.00 how many children attended?
Found 3 solutions by checkley71, joyofmath, praseena:
Answer by checkley71(8403)   (Show Source):
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18A+8C=288 &
A+C=21 THEN
A=21-C NOW REPLACE A BY (21-C) IN THE OTHER EQUATION
18(21-C)+8C=288
378-18C+8C=288
-10C=288-378
-10C=-90
C=-90/-10
C=9 SOLUTION.
THEN
A+9=21
A=21-9
A=12 SOLUTION
PROOF
18*12+8*9=288
216+72=288
288=288
MUCH BETTER PROBLEM!!!

Answer by joyofmath(189)   (Show Source):
You can put this solution on YOUR website!
Let the cost of admission be: and
Let the number of adults = and the number of children =
Then as there were 21 people.
And as $288 was collected.
So,
Since, ,
So,
Or,
Or,
Or,
So,
So, There were 12 adults and since there were 21 people altogether there were 9 children.

Verify this answer by plugging in and in
should = 288.

does indeed = 288.

Answer by praseena(37)   (Show Source):
You can put this solution on YOUR website!

Adult tickets cost $18.00 children cost $8.00 there were 21 people total at the theatre and they collected $288.00 how many children attended?

solution:
let us take number of children = x
then number of adults = 21 - x {because total number is 21

cost of one child's ticket = $ 8
so cost of x childen ticket = x * $ 8
cost of one adult ticket = $ 18
so cost of (21 - x ) tickets = (21 -x ) * $ 18
Total money collected = $ 288
this can be combined like this,
( 21 - x )* 18 + x * 8 = $ 288
remove the brackets by multiplying terms, we have,

21 * 18 - x * 18 + x * 8 = $ 288
378 - 18x + 8x = 288
378 - 10x = 288
378 - 288 = 10 x
90 = 10 x
x = 90/10
x = 9
therefore number of children = 9