# SOLUTION: A farmer bought 100 animals for \$100. Sheep were \$10 each, pigs were \$2 each, and chickens were \$.50 each. How many of each did she buy?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: A farmer bought 100 animals for \$100. Sheep were \$10 each, pigs were \$2 each, and chickens were \$.50 each. How many of each did she buy?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Miscellaneous Word Problems Question 607300: A farmer bought 100 animals for \$100. Sheep were \$10 each, pigs were \$2 each, and chickens were \$.50 each. How many of each did she buy?Answer by Edwin McCravy(8909)   (Show Source): You can put this solution on YOUR website!A farmer bought 100 animals for \$100. Sheep were \$10 each, pigs were \$2 each, and chickens were \$.50 each. How many of each did she buy? ``` S + P + H = 100 10S + 2P + .5H = 100 TWO SOLUTIONS: 1 sheep 1×\$10 = \$10 27 pigs 27×\$2 = \$54 72 hens .5×72 = \$36 ---------------------- 100 animals = \$100 4 sheep 4×\$10 = \$40 8 pigs 8×\$2 = \$16 88 hens .5×88 = \$44 ---------------------- 100 animals = \$100 Edwin```