SOLUTION: Romeo bought a mixture of $0.25 , $0.50 and $0.75 valentines. The number of $0.25 valentines are three more then twice the number of $0.50 valentines. The number of $0.75 valentine

Question 591317: Romeo bought a mixture of $0.25 , $0.50 and $0.75 valentines. The number of $0.25 valentines are three more then twice the number of $0.50 valentines. The number of $0.75 valentines was one less than the number of $0.50 ones. If he spent $5.25 all together how many of each kind did he buy? I need to solve this using letting x represent one number and y represent another.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.25x+.50y+.75z=5.25;
x=3+2y;
z=y-1
x=9
y=3
z=2
check
.25*(9)+.50*3+.75*2=5.25
2.25+1.50+1.50=5.25
5.25=5.25
ok

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