SOLUTION: 14. The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 30 in., find the width of the rectangle. A) 1 in. B) 2 in. C) 3 in. D) 4

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Question 57831: 14. The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 30 in., find the width of the rectangle.
A) 1 in.
B) 2 in.
C) 3 in.
D) 4 in.
Thankyou for your time!!!
Answer by hayek(51) About Me  (Show Source):
You can put this solution on YOUR website!
If l=length and w=width, we have two unknowns. We need two equations to solve for two unknowns.
drawing%28300%2C200%2C0%2C10%2C0%2C10%2Crectangle+%282%2C2%2C8%2C8%29%2C+locate+%285%2C1.5%2Cl%29%2C+locate+%288.5%2C5%2Cw%29%29
The problem gives us both equations:
"The length of a rectangle is 9 in. more than twice its width" ==> l=2w%2B9
"perimeter of the rectangle is 30 in" ==> 2w%2B2l=30
Plug the first equation into the second:
2w%2B2%282w%2B9%29=30
Distribute:
2w%2B4w%2B18=30
6w=12
highlight%28w=2%29inches