SOLUTION: 14. The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 30 in., find the width of the rectangle.
A) 1 in.
B) 2 in.
C) 3 in.
D) 4
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: 14. The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 30 in., find the width of the rectangle.
A) 1 in.
B) 2 in.
C) 3 in.
D) 4
Log On
Question 57831: 14. The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 30 in., find the width of the rectangle.
A) 1 in.
B) 2 in.
C) 3 in.
D) 4 in.
Thankyou for your time!!! Answer by hayek(51) (Show Source):
You can put this solution on YOUR website! If l=length and w=width, we have two unknowns. We need two equations to solve for two unknowns.
The problem gives us both equations:
"The length of a rectangle is 9 in. more than twice its width" ==>
"perimeter of the rectangle is 30 in" ==>
Plug the first equation into the second:
Distribute: inches
(