SOLUTION: A man is twice as old as his son 20 years ago of the man was 12 times the age of the son. Find their present ages. (Ans. 44 Years, 22 Years)

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Question 571445: A man is twice as old as his son 20 years ago of the man was 12 times the age of the son. Find their present ages. (Ans. 44 Years, 22 Years)
Answer by josmiceli(7367) About Me  (Show Source):
You can put this solution on YOUR website!
+f+ = Father's age now
+s+ = Son's age now
+f+-+20+ = Father's age 20 yrs ago
+s+-+20+ - Son's age 20 yrs ago
-----------
given:
(1) +f+=+2s+
(2) +f+-+20+=+12%2A%28+s+-+20+%29+
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(2) +f+-+20+=+12s+-+240+
(2) +12s+-+f+=+220+
Substitute (1) into (2)
(2) +12s+-+2s+=+220+
(2) +10s+=+220+
(2) +s+=+22+
and, since
(1) +f+=+2s+
(1) +f+=+2%2A22+
(1) +f+=+44+
The Father is 44 and the Son is 22