SOLUTION: A truck with 48-in.-diameter wheels is traveling at 45 mi/h.
(a) Find the angular speed of the wheels in rad/min.
rad/min
(b) How many revolutions per minute do the wheels ma
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Question 566223: A truck with 48-in.-diameter wheels is traveling at 45 mi/h.
(a) Find the angular speed of the wheels in rad/min.
rad/min
(b) How many revolutions per minute do the wheels make?
rev/min
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A truck with 48-in.-diameter wheels is traveling at 45 mi/h.
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45 mi/hr = 66 ft/sec = 3960 ft/minute
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Each revolution = pi*d feet = 4pi feet
(b) How many revolutions per minute do the wheels make?
rev/min
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Each revolution = pi*d feet = 4pi feet
rpm = 3960 ft/min / 4pi feet = 990/pi rpm
=~ 315 rpm
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(a) Find the angular speed of the wheels in rad/min.
rad/min
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rad/min = rpm*2*pi
= 990/pi * (2pi)
= 1980 rad/min
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