SOLUTION: Joe has a collection of nickels and dimes that is worth $7.05. If the number of dimes were doubled and the number of nickles were increased by 8, the value of the coins would be $1
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Question 561019: Joe has a collection of nickels and dimes that is worth $7.05. If the number of dimes were doubled and the number of nickles were increased by 8, the value of the coins would be $12.35. How many dimes does he have?
a) 8 dimes b) 43 dimes c) 24 dimes d) 49 dimes
please show work!
THANK YOU!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Joe has a collection of nickels and dimes that is worth $7.05. If the number of dimes were doubled and the number of nickles were increased by 8, the value of the coins would be $12.35. How many dimes does he have?
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Equations:
5n + 10d = 705 cents
5(n+8)+10(2d) = 1235 cents
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5n + 10d = 705
5n + 20d = 1235-40
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Subtract and solve for "d":
10d = 490
d = 49 (# of dimes)
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Solve for "n":
5n + 10d = 705
5n + 490 = 705
5n = 215
n = 43 (# of nickels)
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Cheers,
Stan H.
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a) 8 dimes b) 43 dimes c) 24 dimes d) 49 dimes
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