SOLUTION: The number "N" is a 5 digit natural number. The 6 digit number N1, formed by placing the digit 1 after N, is 3 times as large as the 6 digit number 1N, formed by placing the 1 in

Question 546910: The number "N" is a 5 digit natural number. The 6 digit number N1, formed by placing the digit 1 after N, is 3 times as large as the 6 digit number 1N, formed by placing the 1 in front of N. What is the original 5 digit number N? Write each as an algebraic expression: N1 = ? and 1N = ? Write the equation to solve for finding "N"=
Answer by AnlytcPhil(1806) (Show Source): You can put this solution on YOUR website!
The number "N" is a 5 digit natural number. The 6 digit number N1, formed by placing the digit 1 after N, is 3 times as large as the 6 digit number 1N, formed by placing the 1 in front of N. What is the original 5 digit number N? Write each as an algebraic expression: N1 = ? and 1N = ? Write the equation to solve for finding "N"=

 N = ↏↏↏↏↏
N1 = ↏↏↏↏↏1 = 10N + 1
1N = 1↏↏↏↏↏ = 100000 + N

10N + 1 = 3(100000 + N)
10N + 1 = 300000 + 3N
     7N = 299999
      N =  42857

     N1 = 428571
     1N = 142857

Edwin

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