Call the rate of speed of train A = B-20

Do that because the problem said A's rate is 20 mph less than B's.

D=rt for both, and the t is the same.

Train A:

Divide both sides by B-20, so

Train A:

Train B:

Divide both sides by B.

Train B:

t is the same in both cases, so set the equations equal to each other.

Cross multiply.

Subtract 290B from both sides.

Divide both sides by -100.

Train B's rate = B = 58 mph.

Train A's rate = B-20 = 58-20 = 38mph

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