SOLUTION: I'm supposed to solve, graph and write solution set in interval notation for this problem. And I can't find an example in the book to help me. I was wondering if you could help wit
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Question 53477This question is from textbook Elementary and Intermediate Algebra
: I'm supposed to solve, graph and write solution set in interval notation for this problem. And I can't find an example in the book to help me. I was wondering if you could help with the steps and see if it reminds me how to do this. Thanks..
The average height of the two forwards and the center of a basketball team is 6 feet, 8 inches. What must the average height of the two gaurds be so that the team average is at least 6 feet, 4 inches?
This question is from textbook Elementary and Intermediate Algebra
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The average height of the two forwards and the center of a basketball team is 6 feet, 8 inches. What must the average height of the two gaurds be so that the team average is at least 6 feet, 4 inches?
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The two forwards and the center average 80 inches each.
Let the two guards average "x" inches.
[3(80)+2x]/5>=76
240+2x>=380
2x>=140
x>=70 inches
The average height of the two guards is >= 70 inches.
Cheers,
Stan H.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
(3*80+2X)/5=76*5 OR (240+2X)/5=380 OR 240+2X=1900 OR 2X=1900-240 OR 2X=1660 THUS THE TOTAL HEIGHT OF THE TWO GUARDS MUST BE AT LEAST 1660 INCHES. OR AN AVERAGE OF 5 FT 9 1/6 INCHES.
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