SOLUTION: One-third of the sum of two consecutive integers is 6 less than the smaller integer. Find the integers.

Question 53313: One-third of the sum of two consecutive integers is 6 less than the smaller integer. Find the integers.
Found 2 solutions by Nate, Earlsdon:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
first integer = i
second integer = i + 1
(1/3)(2i + 1) = i - 6
2i + 1 = 3i - 18
19 = i
first integer = 19
second integer = 20
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the smaller integer and x+1 = the next consecutive integer.
Multiply both sides by 3 and simplify.
Subtract 2x from both sides.
Add 18 to both sides.

The two consecutive integers are: 19 and 20
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