SOLUTION: A chemist needs 130 milliliters of a 39% solution but has only 3% and 55% solutions available. How many milliliters of each should be mixed to get the desired solution?

Question 532550: A chemist needs 130 milliliters of a 39% solution but has only 3% and 55% solutions available. How many milliliters of each should be mixed to get the desired solution?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
---------percent ---------------- quantity
Solution I 3 ---------------- x ml
Solution II 55 ------ 130 - x ml
Mixture 39.00% ---------------- 130

3 x + 55 ( 130 - x ) = 39 * 130

3x+7150 -55x=5070
3x-55x=5070-7150
-52x= -2080
/ -52
x=40 ml 3.00% Solution I
90 ml 55.00% Solution II

RELATED QUESTIONS
a chemist needs 130 milliliters of a 79% solution but has only 29% and 94% solutions... (answered by Earlsdon)

15. A chemist needs 130 milliliters of a 47% solution but has only 35% and 87% solutions... (answered by richwmiller)

A chemist needs 130 milliliters of a 47% solution but has only 35% and 87% solutions... (answered by Alan3354)

a chemist needs 130 milliliters of 59% solution but has only 44% and 83% solutions... (answered by Alan3354)

A chemist needs 70 milliliters of a 24% solution but has only 18% and 39% solutions... (answered by josgarithmetic)

A chemist needs 180 milliliters of a 39% solution but has only 15% and 69% solutions... (answered by TimothyLamb)

A chemist needs 100 milliliters of a 63% solution but has only 55% and 95% solutions... (answered by stanbon)

A chemist needs 120 milliliters of a 71% solution but has only 55% and 79% solutions... (answered by josmiceli)

A Chemist needs 120 milliliters of a 21% solution but only has 3% and 27% solutions... (answered by Alan3354)