SOLUTION: I am having a hard time with this word problem:The force of attraction between two bodies varies directly with the product of their masses and inversely with the square of the dist

Algebra.Com
Question 522528: I am having a hard time with this word problem:The force of attraction between two bodies varies directly with the product of their masses and inversely with the square of the distance between them. The force of attraction is 6 pounds when masses of 64 slugs and 108 slugs are 24 feet apart. Find the force of attraction when two masses are 25 slugs each and 60 feet apart.
I know for varies directly the equation would be x=ky and the inversely is z=k/w my problem is I have a hard time pulling out the numbers and putting them in the right part of the equation.
Any help will be appreciated. Thank you

Found 2 solutions by Earlsdon, Edwin McCravy:
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Start with:
Find the value of k by substituting , , and
Solve for k.

Now the equation is:
To find F, substitute , , and .

pounds.

Answer by Edwin McCravy(20064)   (Show Source): You can put this solution on YOUR website!
Rule:

Quantity that varies = k·

>>...The force of attraction between two bodies varies...<<
That's the quantity that varies.  We'll call it F. That goes on
the left of the equal sign.

>>...directly with the product of their masses...<<
So the two masses go on top on the right of the equal sign.  We 
will call them m1 and m2.

>>...and inversely with the square of the distance between them...<<
That's the inversely.  We'll call it d². It goes on the bottom on the 
right. So we have:

              F = k·

That's the incomplete formula.  We must find k before we have the
complete formula:


>>...The force of attraction is 6 pounds when masses of 64 slugs and 108 slugs are 24 feet apart.<<
We substitute F=6, m1=64, m2=108, d=24 

              6 = k·
              6 = k·12
               = k
              0.5 = k

Now we have k.  Now we substitute 0.5 for k in this:

              F = k·

              F = 0.5·

And that is the complete formula.  Now that we have the complete
formula, we are ready to use it.  Here is what we are to use it to
find:

>>..Find the force of attraction when two masses are 25 slugs each and 60 feet apart..<<
We substitute m1 = 25, m2 = 25, d = 60

              F = 0.5·

              F = 0.5·

              F = 0.5·

              F = 0.5·
       
              F = ·

              F = 25/288 = .0868 pounds.

Edwin

RELATED QUESTIONS

Can you please help me with this word problem? The gravitational attraction between... (answered by nyc_function)
Hi, I was hoping to get some help with this problem...... The gravitational attraction (answered by Theo)
Solve the problem as directed. Use proportions to find the solution. The gravitational (answered by stanbon,dfrazzetto)
Using k as the constant of variation, write the equation of variation for each following. (answered by mananth)
The gravitational attraction between two bodies varies inversely as the square of the... (answered by ewatrrr,stanbon)
The force of attraction between two magnets is inversely proportional to the square of... (answered by Alan3354,Boreal)
A force of 100N acting horizontally to the right is to be combined with another force P... (answered by robertb,ikleyn,Edwin McCravy)
Please Help! I am so stumped and confused! :) THANK YOU SO MUCH!!! Gravitational Force (answered by Alan3354)
The gravitational force between two bodies varies inversely as the square of the distance (answered by Theo)