SOLUTION: I am taking an Algebra course in school right now and I am having a bit of trouble with Word problems. Thank you in advance for your help. The question I have tonight is the perime

Question 511615: I am taking an Algebra course in school right now and I am having a bit of trouble with Word problems. Thank you in advance for your help. The question I have tonight is the perimeter of a rectangle is 194 inches. The length exceeds the width by 73 inches. Find the length and the width.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
P = perimeter
L = length
W = width
.
P = 2(L+W) = 2L + 2W
P = 194
.
The length is 73 more than width.
.
L = W+73
or
L-73 = W
.
substitute L = W+73
.
2(L+W) = P
2(W+73 +W) = 194
2W + 146 + 2W = 194
4W = 48
W = 12
.
L = W+73
L = 12+73
L = 85
.
Check to see if the perimeter is correct.
.
2(L+W) = ??
2(85+12) = 2(97) = 194
Correct.
.
Answer: The width = 12. The length = 85.
.
Done.
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