SOLUTION: The sum of two numbers is 130. One number is 46 times more than 1/2 the other number. What are the numbers? Boy do I hate word problems. I can never seem to make sense out

Question 50667: The sum of two numbers is 130. One number is 46 times more than 1/2 the other number. What are the numbers?

Boy do I hate word problems. I can never seem to make sense out of them.
Matt
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x = first number
and y = second number

Now, you need to write two equations since there are two unknowns.
The sum of two numbers is 130.
x+y = 130

One number is 46 times more than 1/2 the other number.
x= 1/2*y+46
If you don't like this equation because of the fraction, just multiply both sides by 2:
2x = y + 92 or 2x-y = 92

There, now it's not a word problem any more. It's solving two equations with two unknowns!!
x+ y = 130
2x -y = 92

Just add the two equations together:
3x= 222
x=74

Now, x + y = 130
so, 74 + y = 130
y=56

Check in the second equation:
x=1/2*y +46
74=1/2*56 + 46
74=28 + 46
It checks!!

R^2 at SCC
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