SOLUTION: I am having problems with this, can someone please help me with this question? The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 squa

Question 49985: I am having problems with this, can someone please help me with this question?
The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 square feet for advertising, find its length and its width.
Answer by alka(15) (Show Source): You can put this solution on YOUR website!
let width = x
length = x+3
area = length * width
40 = X(X+3)
40 = x^2+3x
x^2+3x-40=0
x^2+8x-5x-40=0
x(x+8)-5(x+8)=0
(x+8)(x-5)=0
x=-8 OR x=5
width cannot be negative
width=5feet
length=8feet

RELATED QUESTIONS
Can someone please help me solve this problem. I am having a lot of trouble working it... (answered by funmath)

I am having a hard time with this one question that I have to do for homework, so someone (answered by Alan3354)

I am having a hard time with a question on Exponents and roots. My question is this... (answered by longjonsilver)

The voume (v) of a rectangular solid is 60 cubic meters. Find the length (l) of the... (answered by stanbon)

I am having a hard time with a question can someone help me ? My question is this In a... (answered by prince_abubu)

I am having a hard time with this question can someone help me? My question is this What... (answered by longjonsilver)

I am having trouble with a question, and I think I know the answer and I just need... (answered by Pieter)

the question i am having problem with is: 5x-y=10, what is the value of x. can you please (answered by serenebarril)

I am having a hard time with this Question on Exponents and roots, Can someone help me?... (answered by longjonsilver)