SOLUTION: I am having trouble with word problems: The question I have is: Divide 72 into three parts so that the first part is 3 less than the second part and the third part is 1/2 of the se
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Question 490747: I am having trouble with word problems: The question I have is: Divide 72 into three parts so that the first part is 3 less than the second part and the third part is 1/2 of the second part. I have no idea how to set up the formula and solve it.
Thank you,
Cindy
Found 3 solutions by lwsshak3, josmiceli, MathLover1:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I am having trouble with word problems: The question I have is: Divide 72 into three parts so that the first part is 3 less than the second part and the third part is 1/2 of the second part. I have no idea how to set up the formula and solve it.
**
let x=second part
x-3=first part
x/2=third part
..
all three parts total=72
x+x-3+x/2=72
LCD=2
2x+2x-6+x+144
5x=144+6=150
x=30
Ans:
first part=30-3=27
second part=30
third part=30/2=15
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The simple, direct way is to call the 3 parts
, , and
given:
(1)
(2)
(3)
-------------
Now substitute (2) and (3) into (1)
(1)
Multiply both sides by
(1)
(1)
(1)
and, since
(2)
(2)
(2)
and
(3)
(3)
The parts are 27, 30 and 15
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
let the first part be ,the second part is , and the third part is
given:
the first part is less than the second part
the third part is of the second part
...or
.....solve for
...the first part
now find the second part
and the third part
check:
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