SOLUTION: Let’s say the width of the gravel path is X, Then: 2*12 X +2* 5X + 4X2 = 138 4X2 + 34X –138 = 0 2X2 + 17X –69 = 0 (2X+23)(X-3) = 0 X= -23/2 or 3, X>0 Ans: X= 3 <a href=

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Question 48147: Let’s say the width of the gravel path is X,
Then:
2*12 X +2* 5X + 4X2 = 138
4X2 + 34X –138 = 0
2X2 + 17X –69 = 0
(2X+23)(X-3) = 0
X= -23/2 or 3, X>0
Ans: X= 3

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Answer by cowess(34)   (Show Source): You can put this solution on YOUR website!
Let’s say the width of the gravel path is X,
Then:
2*12 X +2* 5X + 4X2 = 138
4X2 + 34X –138 = 0
2X2 + 17X –69 = 0
(2X+23)(X-3) = 0
X= -23/2 or 3, X>0
Ans: X= 3
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