SOLUTION: A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 336 feet of fencing and does not fence the side along the street
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Question 475831: A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 336 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Assuming that the developer fences three sides of a rectangle, we can define dimensions x and y such that
2x + y = 336
Area = xy
By the AM-GM inequality (Google this if you don't know what it is),
The largest possible area is 14112 ft^2, which occurs in the equality case (2x = y).
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